
Earlier, we solved for the expected payoff of remaining at home: 0.74 (which was a lower expected value than going to the beach when the chance of rain at both was 30%)
What would p_B need to be to yield an expected payoff at the beach of 0.74?
Set 0.74 (expected value of remaining at home) equal to the beach payoffs and solve for p_B
pB * 0.4 + (1 - pB) * 1.0 = 0.74
pB * 0.4 + (1 - pB) * 1.0 = 0.74
pB * 0.4 + 1 - pB = 0.74
pB * 0.4 + 1 - pB = 0.74
pB * -0.6 = -0.26
pB * -0.6 = -0.26
pB = -0.26 / -0.6 = 0.43
When the probability of rain at the beach is 43% (probability of rain at home remains at 30%), we would be indifferent between staying at home & going to the beach.
If the probability of rain at the beach in > 43%, then we would stay home
Suppose we are not certain about the probability of fatal hemorrhage.
At what value of p_fatal_hem would expected survival be equal?
Allow the value of p_fatal_hem to vary over a range.
Find the value of p_fatal_hem along this range where expected survival is equal for the “Anticoagulant” and “No Anticoagulant” strategies.
p_disease), can we make a policy decision?p_disease to vary over a plausible range.