Define treatment thresholds within a decision tree & examine different ways of interpretation
Understand and calculate the value of information from a perfect vs. imperfect test
Treatment thresholds
Testing & Value of Information
What if the probability of recurrent PE were higher or lower than initially estimated?
Perform a sensitivity analysis to find a treatment threshold
(More on sensitivity analyses later in the workshop)
Expected value (AC) = 0.990 * pPE + 0.992 * (1-pPE)
Expected value (No AC) = 0.750 * pPE + 1.0 * (1-pPE)
NOW, SET EQUAL TO EACH OTHER, to solve for unknown threshold probability
0.990 * pPE + 0.992 * (1-pPE) = 0.750 * pPE + 1.0 * (1-pPE)
0.240 * pPE = 0.008 * (1-pPE)
0.240 * pPE + 0.008 *pPE = 0.008
pPE = 0.008 / (0.240 + 0.008)
= .032
Performing a test to gain additional information is ONLY worthwhile IF:
No Treat – Test Threshold
Probability of indifference between testing & not treating
Test – Treat Threshold
Probability of indifference between testing & treatment
Value of information asks: what are we gaining by having this extra information?
Value of information =
|[expected value from the ‘gaining information’ strategy] –
[expected value from the next best strategy]|
PERFECT tests give us an upper limit to the potential benefit from any test
The gain from such an imaginary PERFECT test is the expected value of perfect information (EVPI)

EV(perfect test) = 0.12
EV(treat strategy) = 0.16
EV(no treat strategy) = 0.24 (worst EV)
EVPI =
|EV ‘perfect test’ – EV ‘next best strategy: treat all’|
=|0.12 – 0.16| = 0.04,
or 4 deaths prevented per 100 tests because of the additional testing information
When the test is imperfect, testing is still the best strategy (in this case, the lower EV, the better since our outcome values are the probability of a bad outcome), but not by much:
When the test is IMPERFECT:
EV(test strategy) = 0.157
EV(treat strategy) = 0.16
EV(no treat strategy) = 0.24 (worst EV)
VOI = |EV ‘test’ – EV ‘next best strategy’|
= |0.157 – 0.16| = 0.003,
or 3 deaths prevented per 1000 tests because of the additional testing information